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Events
By place
Roman Empire
- The rebellion of Magnus Maximus is put down at the Battle of the Save, and Valentinian II is restored as Western Roman Emperor. Read full entry
This entry is from Wikipedia,the leading user-contributed encyclopedia.It may not have been reviewed by professional editors(See full disclaimer)
- 1.388 - Wikipedia, the free encyclopedia
- 388. From Wikipedia, the free encyclopedia. Jump to: navigation, search ... article is about the year 388. For the number 388, see 388 (number) ...
- http://en.wikipedia.org/wiki/3
88
- 2.NRS: CHAPTER 388 - SYSTEM OF PUBLIC INSTRUCTION
- NRS 388.030 Division of public schools in school district into departments. ... NRS 388.060 Kindergarten: Establishment; board of trustees authorized ...
- http://www.leg.state.nv.us/NRS
/NRS-388.html
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There are 388 calories and 90g There are 388 calories and 90g
of protein in 100g of protein
powder. How many calories and
how much protein is in 30g of
protein powder?
I think its 116 calories, and
27g of protein.. I know its
simple math but I'm having a
complete brain freeze!
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388/100 = calories per gram of powder 90/100 = grams of protein per gram of powder 3.88*30 = 116.4 calories 30*.90 = 27 grams of protein ... Looks like you're golden |
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What is the simplest formula What is the simplest formula
of a compound if a sample of
the compound contains 0.484
mol X, 3.388 mol Y, and 4.356
mol Z?
How many moles of Z would be
in a sample that contained
0.588 mol X?
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We divide by the smallest number 0.484 / 0.484 = 1 => X 3.388 / 0.484 =7 => Y 4.356 / 0.484 = 9 => Z the formula is XY7Z9 the ratio between X and Z is 1 : 9 moles Z = 0.588 x 9 =5.29 |
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If the gas is compressed Consider a balloon of volume
2.1 m^3 that contains 3.3
moles of helium gas at a
temperature of 318 K.
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The change of the internal energy equals the heat transferred to it and the work done during the process. Since the process is adiabatic not heat is transferred. ΔU = W The internal energy of an ideal gas is given by U = n∙Cv∙T thus, ΔU = n∙Cv∙ΔT Molar heat capacity at constant volume of a monatomic ideal gas like helium is Cv = (3/2)∙R So the work done on the gas is W = ΔU = n∙(3/2)∙R∙ΔT = 3.3mol ∙ (3/2) ∙ 8.314472J/molK ∙ (388K - 318K) = 2881J That means there were -2881J of work done by the gas. |
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