Web Results
  • 1.
    388 - Wikipedia, the free encyclopedia
  • 388. From Wikipedia, the free encyclopedia. Jump to: navigation, search ... article is about the year 388. For the number 388, see 388 (number) ...
  • http://en.wikipedia.org/wiki/388
  • 2.
    NRS: CHAPTER 388 - SYSTEM OF PUBLIC INSTRUCTION
  • NRS 388.030 Division of public schools in school district into departments. ... NRS 388.060 Kindergarten: Establishment; board of trustees authorized ...
  • http://www.leg.state.nv.us/NRS/NRS-388.html
Questions/Answers
There are 388 calories and 90gof protein in 100g of proteinpowder, how many calories &protein is in 30g?
There are 388 calories and 90g of protein in 100g of protein powder. How many calories and how much protein is in 30g of protein powder? I think its 116 calories, and 27g of protein.. I know its simple math but I'm having a complete brain freeze!
388/100 = calories per gram of powder 90/100 = grams of protein per gram of powder 3.88*30 = 116.4 calories 30*.90 = 27 grams of protein ... Looks like you're golden
What is the simplest formulaof a compound if a sample ofthe compound contains 0.484mol X, 3.388 mol Y, and?
What is the simplest formula of a compound if a sample of the compound contains 0.484 mol X, 3.388 mol Y, and 4.356 mol Z? How many moles of Z would be in a sample that contained 0.588 mol X?
We divide by the smallest number 0.484 / 0.484 = 1 => X 3.388 / 0.484 =7 => Y 4.356 / 0.484 = 9 => Z the formula is XY7Z9 the ratio between X and Z is 1 : 9 moles Z = 0.588 x 9 =5.29
If the gas is compressedadiabatically so as to have afinal temperature of 388 K,what is the work done by th?
Consider a balloon of volume 2.1 m^3 that contains 3.3 moles of helium gas at a temperature of 318 K.
The change of the internal energy equals the heat transferred to it and the work done during the process. Since the process is adiabatic not heat is transferred. ΔU = W The internal energy of an ideal gas is given by U = n∙Cv∙T thus, ΔU = n∙Cv∙ΔT Molar heat capacity at constant volume of a monatomic ideal gas like helium is Cv = (3/2)∙R So the work done on the gas is W = ΔU = n∙(3/2)∙R∙ΔT = 3.3mol ∙ (3/2) ∙ 8.314472J/molK ∙ (388K - 318K) = 2881J That means there were -2881J of work done by the gas.
knowledge base
* Indicates a required fieldAdd your knowledge or ask a question:
  • Display Name:(letters/numbers, no special characters)
  • Your knowledge or question:*
    (min: 100 characters, max: 2,000 characters)
  • Character count: 0
© 2010 ToseekA.com
Portions of this page powered by: yahoo!