Questions/Answers
Was the battle of Palashi at1757 for loosing freedom orgaining freedom from tyrantSirajoddoulla?
Our history was wrongly written.Siraj became king at very early age by that time he was completely spoiled due to pampering of his grandfather Alibardi. Whenever siraj saw a beautiful woman,he forcefully brought her into his harem and captivated her lifelong[thousands in no.]. Siraj"s men attack ferry boats across ganges and drown the passengers.From the roof of the palace ,he used to enjoy the scene. His torture on hindus was beyond toleration. Nobody could make wealth from his fear . He used to insult respected persons recklessly.He slapped Juggatseth[famous banker and businessman] in his durbar in front of all. He killed Kuli Khan ,a relative of Ghasseti begum . No person including both hindus and muslims could live a peaceful life in his regime. Even the Darbesh who helped Mirjafar to captivate siraj was a victim of siraj's torture.Siraj cut his nose and ear previously. So all the eminent personalities stood against his.He was described as a good person nowhere in history
The battle was between Siraj Ud Daulah, the last independent Nawab of Bengal, and the forces of the British East India Company. Siraj-ud-Daulah's army commander had defected to the British, causing his army to collapse. After this defeat, the entire province of Bengal passed to the Company, and this battle is today seen as one of the pivotal battles leading to British Empire in India.
my aieee air is 19717(gen) &my state rank is 1757 can iget any nit if yes which onenearest to delhi plzhelp
and my dce rank is 2605 will i be able to get through moreover my ptu rank is 619 can i get through it despite not having punjab domicile please !!!!!!! somebody help me out i m very tensed what to do??????
no
Which fort was built after theBattle of Plassey in 1757?
Fort William
Does anyone have experiencewith selling antique books?
I have four books I bought at a library book sale and I think they are worth something: "Christmas Carol: Cricket on the Hearth", Dickens, hardcover, signed, Haughton/Mifflin Co., 1893. In good condition. "Last of the Mohicans", A Narrative of 1757 by J. Finemore Cooper, Hurst & Co., NY., hardcover. In worn condition. "Mixed Pickles", E.M. Field, 1900, Henry Altenus Co. Good condition. "Keziah Coffin", Joseph C. Lincoln, 1909, D. Appelton & Co., NY and London MCMIX. Good condition
go to www.abebooks.com where you can fill in the search engine with author, title date, etc. you should get a list of copies for sale. Say there are 10 copies for sale. Look at the one in the middle (the fifth copy). that would be your estimate of its worth. I just looked up "Mixed Pickles" for you. It's worth about $10.00 but the signed Dickens should be worth a lot more
Can somebody help me with acalorimetry lab due tomorrow?
Basically I had to take the temperature of a hot piece of metal, 100mL of tap water, place the hot piece of metal in the water (which was placed in a calorimeter), and then take the temperature of the metal, after it had cooled in the tap water. This is my data: Temp. of tap water: 22.8* C Temp. of hot metal: 80.9 *C Temp of water, after the metal has been placed in it: 27.0 *C Mass of metal: 100.52g Heat capacity of water: 4.184 J/g x*C So I need the quantity of heat transferred from the metal to the water, and I need the heat capacity of the metal. The equation is Q=mc(deltaT) Q is the quantity, m is the mass, c is the heat capacity, and delta T is the second temp. minus the first temp. I managed to get the quantity of heat from metal to water, which was 1757.28J, by multiplying out the measurements I got. But I can't get the heat capacity of the metal. I'm not sure which numbers to use to calculate it. Can somebody help?
For the first calculation you need to ignor the mass and temperature of the metal (100ml of water = 100g), and just concentrate on the water, assuming this is what you did you worked out the energy absorbed by the water. This number will be the same as the amount of energy given out by the metal, so you just need to rearrange your formula so: c=mQ(deltaT) Where, c is the heat capacity of the metal, m is the mass of the metal, Q is the energy change (the number you worked out before) and delta T is the change in temp of the metal (not the water) That should give you the answer you need. As you don't have a value for the second temp of the metal then I guess it would be the same as the water.
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